0=-16t^2+1024

Solution for 0=-16t^2+1024 equation:

0=-16t^2+1024

We move all terms to the left:

0-(-16t^2+1024)=0

We add all the numbers together, and all the variables

-(-16t^2+1024)=0

We get rid of parentheses

16t^2-1024=0

a = 16; b = 0; c = -1024;
Δ = b2-4ac
Δ = 02-4·16·(-1024)
Δ = 65536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65536}=256$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-256}{2*16}=\frac{-256}{32}
=-8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+256}{2*16}=\frac{256}{32}
=8
$